What are K and L respectively if 12 1 2 (3y - 4x)2 = (8x2 + kxy + Ly2)

Question 1 Report

What are K and L respectively if $\frac{1}{2}$ (3y - 4x)2 = (8x2 + kxy + Ly2)

-12,

\frac{9}{2}

-6, 9

6, 9

12,

\frac{9}{2}

Answer Details

$\frac{1}{2}$ (3y - 4x)2 = (8x2 + kxy + Ly2)
$\frac{1}{2}$ (9y2 - 24xy + 16x2) = 8x2 + kxy + Ly2
$\frac{9}{2}$ y2 - 12xy) = kxy + Ly2
k = -12 ∴ L = $\frac{9}{2}$

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