If PST is a straight line and PQ = QS = SR in the diagram, find y.

If PST is a straight line and PQ = QS = SR in the diagram, find y.

Answer Details

< PSQ = < SQR = < SRQ = 24${}^{\circ }$

< QSR = 180${}^{\circ }$ - 48${}^{\circ }$ = 132${}^{\circ }$

< PSQ + < QSR + y + 180 (angle on a straight lines)

24 + 132 + y = 180${}^{\circ }$ = 156${}^{\circ }$ + y = 180

y = 180${}^{\circ }$ - 156${}^{\circ }$

= 24${}^{\circ }$