The electrical power developed in the resistor above is
Question 1 Report
The electrical power developed in the resistor above is
Answer Details
The circuit diagram shows a 16 V battery connected to a single 2 Ω resistor in a closed loop. To find the power dissipated in the resistor, use the formula:
\(P = \frac{V^2}{R}\)
Substituting the values:
\(P = \frac{(16)^2}{2} = \frac{256}{2} = 128 \text{ W}\)
The total power dissipated in the circuit is 128 W.
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