The acceleration of the body given above ( upthrust = 10N)
Question 1 Report
The acceleration of the body given above ( upthrust = 10N)
Answer Details
The diagram shows a body of mass 10 kg submerged in a liquid. Three forces act on it:
- Weight (downward) = \(mg = 10 \times 10 = 100\) N
- Upthrust (upward) = 10 N
- Viscous drag (upward, opposing motion) = 15 N
The net downward force is:
\(F_{net} = W - U - F_d = 100 - 10 - 15 = 75\) N
Applying Newton's second law:
\(a = \frac{F_{net}}{m} = \frac{75}{10} = 7.5\) m/s\(^2\)
The body accelerates downward at 7.5 m/s\(^2\).
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