A cell of e.m.f. 1.5V and internal resistance of 2.5Ω is connected in series with an ammeter of resistance 0.5W and a resistor of resistance of 7.0Ω. Calcul...
Question 1 Report
A cell of e.m.f. 1.5V and internal resistance of 2.5Ω is connected in series with an ammeter of resistance 0.5W and a resistor of resistance of 7.0Ω. Calculate the current in the circuit.
Answer Details
To calculate the current in the circuit, we can use Ohm's Law:
V = IR
where V is the voltage (or electromotive force), I is the current, and R is the resistance.
In this case, the voltage of the cell is 1.5V, and the internal resistance of the cell is 2.5Ω. The total resistance in the circuit is the sum of the ammeter resistance (0.5Ω) and the resistor resistance (7.0Ω), which is 7.5Ω.
So, we can write the equation:
1.5V = I (2.5Ω + 7.5Ω)
Simplifying the equation, we get:
1.5V = I (10Ω)
I = 1.5V / 10Ω
I = 0.15A
Therefore, the current in the circuit is 0.15A.
The correct option is (a) 0.15A.
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