A gas occupies a certain volume at 27°C. At what temperature will its volume be three times the original volume assuming that its pressure remains constant?
Question 1 Report
A gas occupies a certain volume at 27°C. At what temperature will its volume be three times the original volume assuming that its pressure remains constant?
Answer Details
The problem can be solved using Charles's law, which states that the volume of a gas at a constant pressure is directly proportional to its temperature in kelvins.
Let the initial temperature of the gas be T1 = 27°C + 273.15 = 300.15 K, and let its initial volume be V1.
According to the problem, when the volume is tripled, the new volume is V2 = 3V1. We want to find the new temperature T2.
Using Charles's law, we can write:
V1 / T1 = V2 / T2
Substituting the values:
V1 / 300.15 = 3V1 / T2
Solving for T2:
T2 = (3V1 x 300.15) / V1 = 900.45 K
Converting back to Celsius:
T2 = 900.45 - 273.15 = 627.3°C (approx)
Therefore, the answer is 627°C.
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