A force F acts on a body of mass 12kg increases its speed from 5 m/s to 35 m/s in 5 seconds. Find the value of F.
Question 1 Report
A force F acts on a body of mass 12kg increases its speed from 5 m/s to 35 m/s in 5 seconds. Find the value of F.
Answer Details
We can use the formula:
$$F = ma$$
where F is the force applied, m is the mass of the body, and a is the acceleration produced.
To find the acceleration, we can use the formula:
$$a = \frac{v_f - v_i}{t}$$
where v_f is the final velocity, v_i is the initial velocity, and t is the time taken.
Substituting the given values, we get:
$$a = \frac{35 - 5}{5} = 6 \text{ m/s}^2$$
Substituting this value of acceleration and the given mass into the formula for force, we get:
$$F = ma = 12 \times 6 = 72 \text{ N}$$
Therefore, the value of F is 72 N.
So, the answer is 72 N.
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