(a) Explain what is meant by the following statement. The specific latent heat of fusion of ice is \(3.4 \times 10^{5}Jkg^{-1}\). (b) Describe an experiment...

Assessment: WAEC SSCE - Physics - 1992 (Essay) Subject: Physics

Question 1 Report

(a) Explain what is meant by the following statement. The specific latent heat of fusion of ice is \(3.4 \times 10^{5}Jkg^{-1}\).

(b) Describe an experiment to determine the specific latent heat of fusion of ice. State two precautions necessary to obtain an accurate result.

(c) Using the kinetic theory of matter, explain why ice can change to water at 0°C without any change in temperature. 

Answer Details

(a) The statement means that \(3.4\times10^{5}\,\text{J}\) of heat is required to change \(1\,\text{kg}\) of ice at \(0^\circ\text{C}\) completely into water at \(0^\circ\text{C}\), without any change in temperature.

(b) Experiment (method of mixtures):

  • Half-fill a lagged calorimeter (of known mass \(m_c\) and specific heat \(c_c\)) with warm water; measure the mass of water \(m_w\) and the initial temperature \(\theta_1\).
  • Dry some small pieces of pure melting ice at \(0^\circ\text{C}\) with blotting paper and drop them into the water; stir until all the ice just melts.
  • Record the lowest (final) temperature \(\theta_2\), and find the mass of ice added \(m_i\) by reweighing.
  • Heat lost by water and calorimeter = heat used to melt the ice + heat to warm the melted ice from \(0^\circ\text{C}\) to \(\theta_2\):
\[ (m_w c_w + m_c c_c)(\theta_1 - \theta_2) = m_i L + m_i c_w(\theta_2 - 0) \]

from which the specific latent heat of fusion \(L\) is calculated.

Two precautions: dry the ice thoroughly and use ice already at \(0^\circ\text{C}\); lag the calorimeter and stir gently to reduce heat exchange with the surroundings.

(c) Kinetic-theory explanation. When ice melts at \(0^\circ\text{C}\), the heat supplied is used to break down the rigid bonds of the ice lattice, increasing the potential energy of the molecules and letting them move past one another as a liquid. It does not increase their average kinetic energy. Since temperature depends on the average kinetic energy of the molecules, the temperature stays constant at \(0^\circ\text{C}\) throughout melting.

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