If the exterior angles of quadrilateral are yo, (y + 5)o, (y + 10)o and (y + 25)o, find y

Assessment: WAEC SSCE - General Mathematics - 1998 (Objective) Subject: General Mathematics

Question 1 Report

If the exterior angles of quadrilateral are y^o, (y + 5)^o, (y + 10)^o and (y + 25)^o, find y

10^o

20^o

40^o

60^o

80^o

Answer Details

The sum of the exterior angles of any polygon is always equal to 360 degrees. Therefore, we can write an equation as: y + (y + 5) + (y + 10) + (y + 25) = 360 Simplifying the equation, we get: 4y + 40 = 360 Subtracting 40 from both sides, we get: 4y = 320 Dividing both sides by 4, we get: y = 80° Therefore, the value of y is 80^o.

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