10.0 dm3 of water was added to 2.0 mol dm-3..

Question 1 Report

10.0 dm3 of water was added to 2.0 mol dm-3 of 2.5dm3 solution of HCl. What is the concentration of the final solution in mol dm-3?

0.4

8.0

2.0

0.5

Answer Details

C1V1 = C2V2

C2 = $\frac{C_{1} V_{1}}{V_{2}}$

= $\frac{2.0 \times 2.5}{12.5}$

= 0.4mol/dm-3