A certain radioisotope of 23592U 92 235 U emits four alpha particles and three beta particles. The mass number and the atomic number of the resulting elemen...

A certain radioisotope of ${}_{92}^{235}U$ emits four alpha particles and three beta particles. The mass number and the atomic number of the resulting elements respectively are

Answer Details

${}_{92}^{235}U$ $\to$ 4${(}_2^4\alpha )$ + 3${(}_{-1}^{0}e)$ + ${}_a^{b}y$

a + (4 + 2) + (3x - 1) = 92 $\Rightarrow$ a = 87

b + (4 x 4) + (3 x 0) = 235 $\Rightarrow$ b = 219

${}_a^{b}Y$ = ${}_{87}^{219}Y$