A car takes off from rest and covers a distance of 80m on a straight road in 10s. Calculate the magnitude of its acceleration
Answer Details
The acceleration of an object is given by the formula:
a = (v - u) / t
where,
a = acceleration
v = final velocity
u = initial velocity
t = time
Here, the car starts from rest, which means its initial velocity (u) is zero. The car covers a distance of 80m in a time of 10s. We can use the formula of distance to find the final velocity of the car.
s = ut + (1/2)at^2
where,
s = distance
u = initial velocity
t = time
a = acceleration
As the car starts from rest, its initial velocity is zero, so we can simplify the equation to:
s = (1/2)at^2
Rearranging the formula to get acceleration (a), we have:
a = 2s / t^2
Substituting the given values, we get:
a = 2 x 80m / (10s)^2 = 1.6ms^-2
Therefore, the magnitude of the car's acceleration is 1.6ms^-2.
The answer is.