A car takes off from rest and covers a distance of 80m on a straight road in 10s. Calculate the magnitude of its acceleration

Assessment: WAEC SSCE - Physics - 2002 (Objective) Subject: Physics

Question 1 Report

A car takes off from rest and covers a distance of 80m on a straight road in 10s. Calculate the magnitude of its acceleration
Answer Details
The acceleration of an object is given by the formula: a = (v - u) / t where, a = acceleration v = final velocity u = initial velocity t = time Here, the car starts from rest, which means its initial velocity (u) is zero. The car covers a distance of 80m in a time of 10s. We can use the formula of distance to find the final velocity of the car. s = ut + (1/2)at^2 where, s = distance u = initial velocity t = time a = acceleration As the car starts from rest, its initial velocity is zero, so we can simplify the equation to: s = (1/2)at^2 Rearranging the formula to get acceleration (a), we have: a = 2s / t^2 Substituting the given values, we get: a = 2 x 80m / (10s)^2 = 1.6ms^-2 Therefore, the magnitude of the car's acceleration is 1.6ms^-2. The answer is.

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