A reservoir is filled with a liquid of density 2000kgm-3. Calculate the depth at which the pressure in the liquid will equal to 9100Nm-2 [g = 10ms-2]
Answer Details
To calculate the depth at which the pressure in the liquid will equal to 9100Nm-2, we can use the formula: pressure = density * gravity * height where density is the density of the liquid, gravity is the acceleration due to gravity, and height is the depth of the liquid. Rearranging this formula to solve for height, we get: height = pressure / (density * gravity) Substituting the given values, we get: height = 9100 / (2000 * 10) = 0.455m Therefore, the depth at which the pressure in the liquid will equal to 9100Nm-2 is 0.455m. So, the answer is.