(a) Copy and complete the table of values for the relation \(y = 3 \sin 2x\). x \(o^o\) \(15^o\) \(30^o\) \(45^o\) \(60^o\) \(75^o\) \(90^o\) \(105^o\) \(12...

Assessment: WAEC SSCE - General Mathematics - 2020 (Essay) Subject: General Mathematics

Question 1 Report

(a) Copy and complete the table of values for the relation \(y = 3 \sin 2x\).

x \(o^o\) \(15^o\) \(30^o\) \(45^o\) \(60^o\) \(75^o\) \(90^o\) \(105^o\) \(120^o\) \(135^o\) \(^o\)
y 0.0 1.5 -2.6

(b) Using a scale of 2 cm to 15° on the x-axis and 2cm to I unit on the y-axis, draw the graph of \(y = 3 \sin 2x\) for \(0° \geq x \geq 150°\).

(c) Use the graph to find the truth set of;

(i) \(3 \sin 2x + 2 = 0\);

(ii ) \(\frac{3}{2} \sin 2x = 0.25\).

Answer Details

(a) Completing the table for \(y=3\sin 2x\) (angles in degrees). For example \(x=30^\circ:\;3\sin 60^\circ=3(0.866)=2.6\).

x0153045607590105120135150
y0.01.52.63.02.61.50.0-1.5-2.6-3.0-2.6

(b) Plot these points and join with a smooth sine curve for \(0^\circ\le x\le 150^\circ\).

(c)(i) \(3\sin 2x+2=0\). This means \(3\sin 2x=-2\), so draw the line \(y=-2\) and read the crossing:

\[ \sin 2x=-\tfrac{2}{3} \Rightarrow 2x=221.8^\circ \Rightarrow x\approx 111^\circ \]

Truth set \(=\{x\approx 111^\circ\}\).

(ii) \(\frac{3}{2}\sin 2x=0.25\). Multiply by 2: \(3\sin 2x=0.5\), so draw the line \(y=0.5\):

\[ \sin 2x=\tfrac{1}{6} \Rightarrow 2x=9.6^\circ \text{ or } 170.4^\circ \Rightarrow x\approx 5^\circ \text{ or } 85^\circ \]

Truth set \(=\{x\approx 5^\circ,\; 85^\circ\}\).

Download The App On Google Playstore

Everything you need to excel in your exams

Green Bridge CBT Mobile App
Personalized AI Learning Chat Assistant
200,000+ Exam Questions Across IGCSE, JAMB, WAEC & NECO
Over 3,900 Lesson Notes
Offline Support - Learn Anytime, Anywhere
Green Bridge Timetable
Literature Summaries & Potential Questions
Track Your Performance & Progress
In-depth Explanations for Comprehensive Learning