If y varies directly s the square root of (x + 1) and y = 6 when x = 3, find x when y = 9

Assessment: WAEC SSCE - General Mathematics - 2013 (Objective) Subject: General Mathematics

Question 1 Report

If y varies directly s the square root of (x + 1) and y = 6 when x = 3, find x when y = 9
Answer Details
We are given that y varies directly with the square root of (x+1), which can be written as y=k√(x+1), where k is the constant of variation. To find k, we use the given values of x and y: y=k√(x+1) 6=k√(3+1) 6=k√4 6=2k k=3 So the equation for y in terms of x is y=3√(x+1). To find x when y=9, we substitute these values into the equation and solve for x: 9=3√(x+1) 3=√(x+1) 9=x+1 x=8 Therefore, x = 8 when y = 9.
Read lesson note on Variation (WAEC)
Read lesson note on Variation (JAMB)
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