23592U+10n→14456Ba+9036Kr+2X 92 235 U + 0 1 n → 56 144 B a + 36 90 K r + 2 X In the reaction above, X is

Question 1 Report

$_{92}^{235} U +_{0}^{1} n \to_{56}^{144} B a +_{36}^{90} K r + 2 X$

In the reaction above, X is

electron

proton

neutrino

neutron

Structure Of The Atom (Nigeria Only)

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