106J of heat is required to boil off completely 2kg of a certain liquid. Neglecting heat lost to the surroundings, the latent heat of vaporization of the li...
Question 1 Report
106J of heat is required to boil off completely 2kg of a certain liquid. Neglecting heat lost to the surroundings, the latent heat of vaporization of the liquid is
Answer Details
The latent heat of vaporization of a substance is the amount of heat energy required to completely vaporize a unit mass of the substance at constant temperature and pressure, without a change in temperature.
In this case, 10^6 J of heat energy is required to completely vaporize 2 kg of the liquid. We can find the latent heat of vaporization using the formula:
Latent heat of vaporization = Heat energy required / Mass of substance
Therefore, the latent heat of vaporization of the liquid is:
10^6 J / 2 kg = 5 x 10^5 J/kg
So, the correct option is "5.0 x 10^5 J/kg".
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