A piece of brass of mass 170kg has its temperature raised from 0oC to 30oC. Calculate its increase in volume, given the density of brass at 0oC as 8.5 x 103...
A piece of brass of mass 170kg has its temperature raised from 0oC to 30oC. Calculate its increase in volume, given the density of brass at 0oC as 8.5 x 103kgm3 and its cubic expansivity as 5.7 x 10-1k1
Answer Details
When a material is heated, it expands. The increase in volume can be calculated using the following formula:
ΔV = VαΔT
Where ΔV is the change in volume, V is the original volume, α is the coefficient of linear or cubic expansivity depending on the type of expansion, and ΔT is the change in temperature.
For a cubic expansivity, the formula can be written as:
ΔV = VβΔT
Where Vβ is the coefficient of cubic expansivity.
Using the given values, the increase in volume of the brass can be calculated as:
ΔV = VβΔT = Vβ(Tf - Ti)
Where Tf is the final temperature and Ti is the initial temperature.
The initial volume of the brass can be calculated using its mass and density:
V = m/ρ = 170/8.5 x 10^3 = 0.02 m^3
Substituting the values, we get:
ΔV = Vβ(Tf - Ti) = 0.02 x 5.7 x 10^-3 x (30 - 0) = 3.42 x 10^-5 m^3
Therefore, the increase in volume of the brass is 3.42 x 10^-5 m^3.
The correct option is (a) 3.4 x 10^-5 m^3.