Question 1 Report
A given mass of an ideal gas occupies a volume V at a temperature T and under a pressure p. If the pressure is increased to 2p and the temperature reduced to \( \frac{1}{2T} \), then the percentage change in the volume of the gas is
P2 = 2P1
T1 = 2T2
=
V2 --V1
% change = X 100%
= 75%
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