An electron of charge 1.60 x 10\(^{-19}\)C is accelerated under a potential difference of 1.0 x 10\(^{5}\) V. Calculate the energy of the electron in joules...
Question 1 Report
An electron of charge 1.60 x 10\(^{-19}\)C is accelerated under a potential difference of 1.0 x 10\(^{5}\) V. Calculate the energy of the electron in joules.
Answer Details
Energy gained by an accelerated electron
When a charge \(q\) is accelerated through a potential difference \(V\), the energy it gains is the work done on it:
\[ E = qV \]Substituting \(q = 1.60\times10^{-19}\,\text{C}\) and \(V = 1.0\times10^{5}\,\text{V}\):
\[ E = (1.60\times10^{-19})(1.0\times10^{5}) = 1.6\times10^{-14}\,\text{J} \]The energy of the electron is \(1.6\times10^{-14}\,\text{J}\).
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