Question 1 Report
(a)(i) State the two types of hardness in water.
(ii) Name a salt that causes each type of hardness.
(ii) Write a balanced equation for the removal of each type of hardness.
(iv) State one effect of hard water on soap.
(b)(i) State whether the pH of each of the following is less than, equal to, or greater than 7.
I. Glucose solution II. Chlroine water III. Lime water IV. Sour milk
(ii) Give the difference between the following compounds: I. an acidic oxide and an amphoteric oxide; II. concentrated acid and a dilute acid; Ill. a normal salt and an acid salt
(c)(i) Iron reacts with H\(_2\)SO\(_4\) according to the equation: Fe\(_{(s)}\) + H\(_2\)SO\(_{4(aq)}\) ---> FeSO\(_{4(aq)}\) + H\(_{2(g)}\)
Calculate the mass of FeSO\(_4\) that would be produced by 0.5 mole of Fe. [H = 1, S = 32, Fe = 56]
(ii) List two allotropes of sulphur
(d)(i) State what would La observed when a damp starch-iodide paper is dropped into a gas jar of chloride
(ii) Explain your ansv.er in (d)(i) above.
(iii) State the products formed when ammonia reacts with excess chlorine.
(a) Hardness of water
(b)(i) pH values
(b)(ii) Differences
(c)(i) Mass of FeSO4 from 0.5 mole of Fe
From Fe + H2SO4 → FeSO4 + H2, the mole ratio Fe : FeSO4 is 1 : 1, so moles of FeSO4 = 0.5 mol.
Molar mass of FeSO4 = 56 + 32 + 64 = 152 g mol-1.
Mass = 0.5 × 152 = 76 g.
(c)(ii) Rhombic sulphur and monoclinic sulphur.
(d)(i) The damp starch-iodide paper turns blue-black.
(d)(ii) Chlorine is a stronger oxidizing agent than iodine; it oxidizes the iodide ions on the paper to iodine, and the liberated iodine turns the starch blue-black.
(d)(iii) With excess chlorine, ammonia gives nitrogen trichloride (NCl3) and hydrogen chloride: NH3 + 3Cl2 → NCl3 + 3HCl.
Everything you need to excel in your exams