The triangle PQR above is

Assessment: JAMB UTME - Mathematics - 2002 Subject: General Mathematics

Question 1 Report

The triangle PQR above is

Answer Details
∠PQR = 180 - 128 (∠s on a straight line)
= 52 ∘
∠QPR + 76 + 52 = 180(extr ∠ = sum of intr. opp ∠s)
∠QPR + 128 = 180
∠QPR = 180 - 128
= 52 ∘
∴ΔPQR is an isosceles triangle
Read lesson note on Circles (WAEC)
Read lesson note on Triangles And Polygons (WAEC)
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