Question 1 Report
The triangle PQR above is
Answer Details
∠PQR = 180 - 128 (∠s on a straight line) = 52∘ ∘ ∠QPR + 76 + 52 = 180(extr ∠ = sum of intr. opp ∠s) ∠QPR + 128 = 180 ∠QPR = 180 - 128 = 52∘ ∘ ∴ΔPQR is an isosceles triangle
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