If x varies directly as √n and x = 9 when n = 9, find x when n = (17/9)
Question 1 Report
If x varies directly as √n and x = 9 when n = 9, find x when n = (17/9)
Answer Details
If x varies directly as the square root of n, we can write the equation as:
x = k√n
where k is a constant of proportionality. To find k, we can use the given values of x and n:
9 = k√9
Solving for k, we get:
k = 3
So the equation becomes:
x = 3√n
To find x when n = 17/9, we substitute n into the equation:
x = 3√(17/9) = 3(√17/√9) = 3(√17/3) = √17
Therefore, x = √17.
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