If f(x)=3x3+4x2+x−8 f ( x ) = 3 x 3 + 4 x 2 + x − 8 , what is the value of f(-2)?

If $f\left(x\right)=3x^3+4x^2+x-8$, what is the value of f(-2)?

Answer Details

To find the value of f(-2), we need to substitute x = -2 into the equation f(x) = 3x^3 + 4x^2 + x - 8. So, f(-2) = 3(-2)^3 + 4(-2)^2 + (-2) - 8 = -24 + 16 - 2 - 8 = -18 Therefore, the value of f(-2) is -18.