If \(f(x)=3x^3+4x^2+x-8\), what is the value of \(f(-2)\)?

Assessment: JAMB UTME - Mathematics - 2019 Subject: General Mathematics

Question 1 Report

If \(f(x)=3x^3+4x^2+x-8\), what is the value of \(f(-2)\)?

Answer Details
To find the value of f(-2), we need to substitute x = -2 into the equation f(x) = 3x^3 + 4x^2 + x - 8. So, f(-2) = 3(-2)^3 + 4(-2)^2 + (-2) - 8 = -24 + 16 - 2 - 8 = -18 Therefore, the value of f(-2) is -18.

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