If \(f(x)=3x^3+4x^2+x-8\), what is the value of \(f(-2)\)?
Answer Details
To find the value of f(-2), we need to substitute x = -2 into the equation f(x) = 3x^3 + 4x^2 + x - 8. So,
f(-2) = 3(-2)^3 + 4(-2)^2 + (-2) - 8 = -24 + 16 - 2 - 8 = -18
Therefore, the value of f(-2) is -18.