If y=6x3+2x−2−x−3 y = 6 x 3 + 2 x − 2 − x −..

Question 1 Report

If $y = 6 x^{3} + 2 x^{- 2} - x^{- 3}$ , find $\frac{d y}{d x}$ .

\frac{d y}{d x} = 15 x^{2} - 4 x^{- 2} - 3 x^{- 2}

\frac{d y}{d x} = 6 x + 4 x^{- 1} - 3 x^{- 4}

\frac{d y}{d x} = 18 x^{2} - 4 x^{- 3} + 3 x^{- 4}

\frac{d y}{d x} = 12 x^{2} + 4 x^{- 1} - 3 x^{- 2}

Answer Details

$y = 6 x^{3} + 2 x^{- 2} - x^{- 3}$
$\frac{d y}{d x} = 18 x^{2} - 4 x^{- 3} + 3 x^{- 4}$

If y=6x3+2x−2−x−3 y = 6 x 3 + 2 x − 2 − x − 3 , find dydx d y d x .