If $y = 6x^3 + 2x^{-2} - x^{-3}$, find $\frac{dy}{dx}$.

Assessment: JAMB UTME - Mathematics - 2019 Subject: General Mathematics

Question 1 Report

\frac{d y}{d x} = 15 x^{2} - 4 x^{- 2} - 3 x^{- 2}

\frac{d y}{d x} = 6 x + 4 x^{- 1} - 3 x^{- 4}

\frac{d y}{d x} = 18 x^{2} - 4 x^{- 3} + 3 x^{- 4}

\frac{d y}{d x} = 12 x^{2} + 4 x^{- 1} - 3 x^{- 2}

Answer Details

$y = 6 x^{3} + 2 x^{- 2} - x^{- 3}$
$\frac{d y}{d x} = 18 x^{2} - 4 x^{- 3} + 3 x^{- 4}$

If \(y = 6x^3 + 2x^{-2} - x^{-3}\), find \(\frac{dy}{dx}\).