If sinx=45 sin ⁡ x = 4 5 , find 1+cot2xcsc2..

Question 1 Report

If $\sin x = \frac{4}{5}$ , find $\frac{1 + \cot^{2} x}{\csc^{2} x - 1}$ .

\frac{13}{2}

\frac{25}{9}

\frac{3}{13}

\frac{4}{11}

Answer Details

$\sin x = \frac{o p p}{H y p} = \frac{4}{5}$
5 $^{2}$ = 4 $^{2}$ + adj $^{2}$
adj $^{2}$ = 25 - 16 = 9
adj = $\sqrt{9}$ = 3
$\tan x = \frac{4}{3}$
$\cot x = \frac{1}{\frac{4}{3}} = \frac{3}{4}$
$\cot^{2} x = (\frac{3}{4})^{2} = \frac{9}{16}$
$\csc x = \frac{1}{\sin x}$
= $\frac{1}{\frac{4}{5}} = \frac{5}{4}$
$\csc^{2} x = (\frac{5}{4})^{2} = \frac{25}{16}$
$∴ \frac{1 + \cot^{2} x}{\csc^{2} x - 1} = \frac{1 + \frac{9}{16}}{\frac{25}{16} - 1}$
= $\frac{25}{16} \div \frac{9}{16}$
= $\frac{25}{9}$

Read lesson note on Sine, Cosine And Tangent Of An Angle (WAEC)

Read lesson note on Probability (JAMB)

Sine, Cosine And Tangent Of An Angle

Probability

View Answer

If sinx=45 sin ⁡ x = 4 5 , find 1+cot2xcsc2x−1 1 + cot 2 ⁡ x csc 2 ⁡ x − 1 .

Download The App On Google Playstore