If 0.0000152 x 0.042 = A x 108, where 1 ≤ ≤ A < 10, find A and B

Assessment: JAMB UTME - Mathematics - 1983 Subject: General Mathematics

Question 1 Report

If 0.0000152 x 0.042 = A x 108, where 1 $\leq$ A < 10, find A and B

A = 9, B = 6.38

A = 6.38, B = -9

A = -6.38, B = -9

A = -9, B = -6.38

Answer Details

0.0000152 x 0.042 = A x 108

1 $\leq$ A < 10, it means values of A includes 1 - 9

0.0000152 = 1.52 x 10-5

0.00042 = 4.2 x 10-4

1.52 x 4.2 = 6.384

10-5 x 10-4

= 10-5-4

= 10-9

= 6.38 x 10-9

A = 6.38, B = -9

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