Question 1 Report
If \(0.0000152 \times 0.042 = A \times 10^8\), where \(1 \le A < 10\), find A and B
A = 9, B = 6.38
A = 6.38, B = -9
A = -6.38, B = -9
A = -9, B = -6.38
Answer Details
0.0000152 x 0.042 = A x 1081 ≤ ≤ A < 10, it means values of A includes 1 - 90.0000152 = 1.52 x 10-50.00042 = 4.2 x 10-41.52 x 4.2 = 6.38410-5 x 10-4= 10-5-4= 10-9= 6.38 x 10-9A = 6.38, B = -9
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