Question 1 Report
The engine of a car provides a forward force of \(1240\ \mathrm{N}\) and the total resistive force on the car is \(800\mathrm{N}\). If the mass of the car is \(1220\ \mathrm{kg}\), determine the distance the car has to travel from the rest before acquiring a speed of \(4\ \mathrm{m\ s^{-1}}\).
Acceleration[a] = [forward−resistive]forcemass
a = 1240−8001220 → 440−8001220
a = 0.36m/s2, v = 4m/s, s = ?
Second equation of motion:
s is distance
u is initial velocity
v is final velocity
a is acceleration
v2 = u2 + 2as
42 = 02 + 2 * 0.36 * s
16 = 0.72s
22.2m = s
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