The diagram shows a marine scientist using a data logger on a buoy. A battery powers a sensor and a transmitter in parallel. The sensor branch takes 0.10 A ...
Question 1 Report
The diagram shows a marine scientist using a data logger on a buoy. A battery powers a sensor and a transmitter in parallel. The sensor branch takes 0.10 A and the transmitter branch takes 0.35 A. The battery potential difference is 9.0 V.
(a) What is the total current supplied by the battery? [1]
(b) What power is supplied by the battery? [2]
(c) Which branch still operates if the transmitter branch becomes disconnected? [1]
(d) What is the potential difference across the sensor? [1]
(e) When the transmitter is switched off, what happens to total current from the battery? [1]
Answer Details
(a) In parallel, currents in branches add:
\[I_\text{total}=0.10+0.35=0.45\text{ A}\] [1]
(b) Use \(P=IV\):
\[P=0.45\times9.0=4.05\text{ W}\approx4.1\text{ W}\] [2]
(c) The sensor branch still operates because it has its own complete parallel branch. [1]
(d) The potential difference across the sensor is 9.0 V. Every parallel branch is connected across the supply. [1]
(e) The total current decreases to \(0.10\text{ A}\), since the disconnected transmitter branch no longer takes \(0.35\text{ A}\). [1]
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