This diagram is of a water-treatment tank where sodium carbonate solution is added to acidic water. The operator has 2.50 dm3 of sodium carbonate solution a...

Assessment: Chemistry 9202 | Paper 2 Mock 01 | Written Paper 2 Subject: Chemistry - 9202

Question 1 Report

This diagram is of a water-treatment tank where sodium carbonate solution is added to acidic water. The operator has 2.50 dm3 of sodium carbonate solution at a concentration of 0.0800 mol dm-3. The tank display records the volume pumped. The carbonate reacts with acid and can form carbon dioxide gas.

Na2CO3 solutiontreatment tank© EAGLE BEACON GLOBAL

(a) Use the concentration and volume to calculate the amount of sodium carbonate pumped into the tank. [2]
(b) Give the volume in cm3 shown by 2.50 dm3. [1]
(c) Describe one observation if excess acid reacts with carbonate in the tank. [2]



Fig. 1 shows a student warming a solid sample of hydrated sodium carbonate before preparing a solution. The student should not heat the compound in this method because the measured mass is needed for an accurate molar concentration. The student dissolves 14.3 g of Na2CO3.10H2O and makes 500 cm3 of solution. Its relative formula mass is 286.

heat sourcevolumetric flask© EAGLE BEACON GLOBAL

(a) Use the mass and relative formula mass to calculate the amount of hydrated sodium carbonate. [2]
(b) Give the concentration of the solution in mol dm-3. [2]
(c) Describe why heating the hydrated solid before weighing would give an unreliable concentration. [1]

Answer Details

Sodium carbonate treatment solution

(a) Use \(n=cV\):

\[n=0.0800\times2.50=0.200\text{ mol}\]

The amount pumped into the tank is 0.200 mol of sodium carbonate. [2 marks]

(b)

\[2.50\text{ dm}^3=2500\text{ cm}^3\]

The displayed volume is 2500 cm3. [1 mark]

(c) Bubbles or effervescence would be observed because carbon dioxide gas is produced when excess acid reacts with carbonate. [2 marks]

Hydrated sodium carbonate solution

(a)

\[n=\frac{m}{M_r}=\frac{14.3}{286}=0.0500\text{ mol}\]

The amount of hydrated sodium carbonate is 0.0500 mol. [2 marks]

(b)

\[500\text{ cm}^3=0.500\text{ dm}^3\]

\[c=\frac{0.0500}{0.500}=0.100\text{ mol dm}^{-3}\]

The concentration is 0.100 mol dm-3. [2 marks]

(c) Heating can remove water of crystallisation, changing the mass and composition of the hydrated solid. The amount calculated from the original formula mass would then be unreliable. [1 mark]

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