Four interior angles of a pentagon are 90o - xo, 90o + xo, 110o - 2xo, 110o + 2xo. Find the fifth interior angle
Answer Details
Let the fifth interior angle be y: sum of interior angle of a pentagon = (2 x 5 - 4) x 90o = 6 x 90o = 540o (90 - x) + (90 + x) + (110 - 2x) + (110 + 2x) + y = 540o 400o + y = 540o y = 540 - 400o y = 140o