PQR is a triangle in which PQ = 10cm and QPR = 60oS is a point equidistant from P and Q. Also S is a point equidistant from PQ and PR. If U is the foot of t...

Question 1 Report

PQR is a triangle in which PQ = 10cm and QPR = 60oS is a point equidistant from P and Q. Also S is a point equidistant from PQ and PR. If U is the foot of the perpendicular from S on PR, find the length SU in cm to one decimal place

2.7

4.33

3.1

3.3

Answer Details

$△$ PUS is right angled
$\frac{U S}{5}$ = sin60o
US = 5 x $\frac{\sqrt{3}}{2}$
= 2.5 $\sqrt{3}$
= 4.33cm

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