PQR is a triangle in which PQ = 10cm and QPR = 60oS is a point equidistant from P and Q. Also S is a point equidistant from PQ and PR. If U is the foot of t...

Assessment: JAMB UTME - Mathematics - 1988 Subject: General Mathematics

Question 1 Report

PQR is a triangle in which PQ = 10cm and QPR = 60oS is a point equidistant from P and Q. Also S is a point equidistant from PQ and PR. If U is the foot of the perpendicular from S on PR, find the length SU in cm to one decimal place
Answer Details
△ PUS is right angled
U S 5  = sin60o
US = 5 x  3 2
= 2.5 3
= 4.33cm

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