In triangle PQR, PQ = 1cm, QR = 2cm and PQR = 120o Find the longest side of the triangle

Assessment: JAMB UTME - Mathematics - 1988 Subject: General Mathematics

Question 1 Report

In triangle PQR, PQ = 1cm, QR = 2cm and PQR = 120o Find the longest side of the triangle
Answer Details
PR2 = PQ2 + QR2 - 2(QR)(PQ) COS 120o
PR2 = 12 + 22 - 2(1)(2) x - cos 60o
= 5 - 2(1)(2) x - 1 2
= 5 + 2 = 7
PR =  7 cm

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