Question 1 Report
In triangle PQR, PQ = 1cm, QR = 2cm and PQR = 120o Find the longest side of the triangle
Answer Details
PR2 = PQ2 + QR2 - 2(QR)(PQ) COS 120o PR2 = 12 + 22 - 2(1)(2) x - cos 60o = 5 - 2(1)(2) x -12 1 2 = 5 + 2 = 7 PR = √7 7 cm
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