If \(\sin\theta = \frac{3}{5}, 0° < \theta ..

Question 1 Report

If \(\sin\theta = \frac{3}{5}, 0° < \theta < 90°\), evaluate \(\cos(180 - \theta)\).

\(\frac{4}{5}\)

\(\frac{3}{5}\)

\(\frac{-3}{5}\)

\(\frac{-4}{5}\)