The percentage of hydrogen in the sixth member of the class of the aliphatic alkanes is [H =1, C =12 ]
Answer Details
To determine the percentage of hydrogen in the sixth member of aliphatic alkanes, we first need to understand the general formula for alkanes. Aliphatic alkanes are a class of hydrocarbons with the general formula CnH2n+2, where 'n' is the number of carbon atoms.
The sixth member of this series will have n = 6. Therefore, the molecular formula for the sixth member is C6H14.
To find the percentage of hydrogen, we first calculate the molar mass of C6H14:
Molar mass of 1 carbon atom = 12
Molar mass of 6 carbon atoms = 6 × 12 = 72
Molar mass of 1 hydrogen atom = 1
Molar mass of 14 hydrogen atoms = 14 × 1 = 14
Total molar mass of C6H14 = 72 + 14 = 86
Next, we calculate the percentage of hydrogen:
Percentage of hydrogen = (Molar mass of hydrogen atoms / Total molar mass) × 100
Percentage of hydrogen = (14 / 86) × 100 = 16.28%
Therefore, the percentage of hydrogen in the sixth member of the aliphatic alkanes is 16.28%.