Cx x Hy y O + 5O2 2 → 4CO2 2 + 4H2 2 O Cx x Hy y O in the equation is

Question 1 Report

C $_{x}$ H $_{y}$ O + 5O $_{2}$ → 4CO $_{2}$ + 4H $_{2}$ O

C $_{x}$ H $_{y}$ O in the equation is

CH

_{2}

O

C

_{2}

H

_{6}

O

CH

_{4}

O

C

_{2}

H

_{4}

O

Answer Details

C $_{x}$ H $_{y}$ O + 5O $_{2}$ → 4CO $_{2}$ + 4H $_{2}$ O

On balancing the equation, we should have

X = 4 , y = 8 and O = 2 ⇒ C $_{4}$ H $_{8}$ O $_{2}$

Since 2 is a common factor to the three atoms, we can divide through by 2, considering the fact that that formula is not in the option.

We finally have C $_{2}$ H $_{4}$ O

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