Question 1 Report
Two inductors of inductance 4 II and 8 II are arrange in series and a current of 10 A is passed through them. What is the energy stored in them?
Answer Details
Effective inductance (1)/L = (1)/4 + (1)/8 = (3)/8 ∴ L = (8)/3 Energy stored = (1)/2 LI2 = (1)/2 x (8)/3 x 10 x 10 = (400)/3 = 133.3 J