A boat sails 8 km north from P to Q and the..

Question 1 Report

A boat sails 8 km north from P to Q and then sails 6 km west from Q to R. Calculate the bearing of R from P. Give your answer to the nearest degree.

217

^{o}

323

^{o}

037

^{o}

053

^{o}

Answer Details

tan θ = $\frac{o p p}{a d j} = \frac{R Q}{Q P} = \frac{6}{8}$

tan θ = 0.75

θ = tan $^{- 1} (0.75) = {36.87}^{o}$

$^{- 1} (0.75) = {36.87}^{o}$
∴ The bearing of R from P = 360 $^{o}$ - 36.87 $^{o}$ = 323 $^{o}$ (to the nearest degree)