(a) Solve : \(7x + 4 < \frac{1}{2}(4x + 3)\). (b) Salem, Sunday and Shaka shared a sum of N1,100.00. For every N2.00 that Salem gets, Sunday gets 50 kobo an...
Question 1 Report
(a) Solve : \(7x + 4 < \frac{1}{2}(4x + 3)\).
(b) Salem, Sunday and Shaka shared a sum of N1,100.00. For every N2.00 that Salem gets, Sunday gets 50 kobo and for every N4.00 Sunday gets, Shaka gets N2.00. Find Shaka's share.
Answer Details
(a) \(7x + 4 < \tfrac{1}{2}(4x + 3)\).
Multiply the bracket: \(7x + 4 < 2x + \tfrac{3}{2}.\)
\(7x - 2x < \tfrac{3}{2} - 4 \Rightarrow 5x < -\tfrac{5}{2} \Rightarrow x < -\tfrac{1}{2}.\)
Solution: \(\mathbf{x < -0.5}.\)
(b) For every \(\text{N}2.00\) Salem gets, Sunday gets \(50\) kobo \((\text{N}0.50)\): so Salem : Sunday \(= 2 : 0.5 = 4 : 1.\)
For every \(\text{N}4.00\) Sunday gets, Shaka gets \(\text{N}2.00\): so Sunday : Shaka \(= 4 : 2 = 2 : 1.\)
Make Sunday common: Salem : Sunday \(= 8 : 2\) and Sunday : Shaka \(= 2 : 1\), giving \[\text{Salem : Sunday : Shaka} = 8 : 2 : 1.\] Total parts \(= 11\). One part \(= \dfrac{\text{N}1100}{11} = \text{N}100.\)
Shaka's share \(= 1 \times \text{N}100 = \mathbf{\text{N}100.00}.\)
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