Solve the equation: 3a + 10 = a\(^2\)

To solve the given equation, we need to bring all the terms to one side and then factorize it to find the values of 'a'. We start by subtracting '3a' from both sides of the equation: 3a + 10 - 3a = a^2 - 3a 10 = a^2 - 3a Now, we can rearrange the terms and factorize the equation as: a^2 - 3a - 10 = 0 (a - 5)(a + 2) = 0 Using the zero product property, we get: a - 5 = 0 or a + 2 = 0 a = 5 or a = -2 Therefore, the values of 'a' that satisfy the given equation are a = 5 or a = -2. Hence, the answer is a = 5 or a = -2.