Find the equation of the straight line through (-2, 3) and perpendicular to 4x + 3y - 5 = 0
Answer Details
4x + 3y - 5 = 0 (given) The equation of the line perpendicular to the given line takes the form 3x - 4y = k Thus, substitution x = -2 and y = 3 in 3x - 4y = k gives; 3(-2) - 4(3) = k -6 - 12 = k k = -18 Hence the required equation is 3x - 4y = -18 3x - 4y + 18 = 0