make u the subject in x =\(\frac{2u-3}{3u + 2}\)

Question 1 Report

make u the subject in x =\(\frac{2u-3}{3u + 2}\)

u = \(\frac{2x + 3}{3x - 2}\)

u = \(\frac{2x - 3}{3x - 2}\)

u = \(\frac{2x + 3}{2 - 3x}\)

u = \(\frac{2x + 3}{3x + 2}\)

Change Of Subject Of A Formula/Relation

Solution Of Linear Equations

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