A parallel plate capacitor of capacitance 600\(\mu F\) has a potential difference of 200V between its plates. Calculate the charge on either plate of the ca...
Question 1 Report
A parallel plate capacitor of capacitance 600\(\mu F\) has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor
Answer Details
The charge on the plates of a capacitor is given by the formula:
Q = C x V
where Q is the charge on the plate, C is the capacitance of the capacitor, and V is the potential difference across the plates.
Substituting the given values, we have:
Q = 600 x 10^-6 F x 200V
Simplifying, we get:
Q = 0.12 C
Therefore, the charge on either plate of the capacitor is 0.12 coulombs or 120 milli-coulombs (mC).
So, the answer is 1.2C.
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