A body of mass 25kg, moving at 3ms-1 on a rough horizontal floor is at rest after sliding through a distance of 2.50m on the floor. Calculate the co-efficie...

Assessment: WAEC SSCE - Physics - 2005 (Objective) Subject: Physics

Question 1 Report

A body of mass 25kg, moving at 3ms-1 on a rough horizontal floor is at rest after sliding through a distance of 2.50m on the floor. Calculate the co-efficient of sliding friction. [g = 10.0ms-2]

Answer Details
To calculate the coefficient of sliding friction, we need to use the equation: frictional force = coefficient of sliding friction x normal force First, let's calculate the initial kinetic energy of the body: Kinetic energy = 0.5 x mass x velocity^2 = 0.5 x 25 x (3)^2 = 112.5 J Next, we need to calculate the work done by the frictional force, which is equal to the initial kinetic energy minus the final kinetic energy (since the body comes to rest): Work done by friction = initial kinetic energy - final kinetic energy = 112.5 - 0 = 112.5 J Now, let's calculate the frictional force: Frictional force = work done by friction / distance = 112.5 / 2.50 = 45 N Finally, we can calculate the coefficient of sliding friction: Coefficient of sliding friction = frictional force / normal force To find the normal force, we can use Newton's second law of motion: Sum of forces = mass x acceleration Since the body is at rest, the acceleration is 0, and the sum of forces is equal to the weight of the body: Sum of forces = weight = mass x gravity = 25 x 10 = 250 N Therefore, the normal force is 250 N. Now we can calculate the coefficient of sliding friction: Coefficient of sliding friction = frictional force / normal force = 45 / 250 = 0.18 Therefore, the coefficient of sliding friction is 0.18. Answer: The coefficient of sliding friction is 0.18.

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