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Find the value of ∫π0cos2θ−1sin2θdθ
Question 1
Report
Find the value of
∫
π
0
c
o
s
2
θ
−
1
s
i
n
2
θ
d
θ
π
π/2
-π/2
-π
Answer Details
∫
π
0
c
o
s
2
θ
−
1
s
i
n
2
θ
d
θ
=
∫
π
0
−
s
i
n
2
θ
s
i
n
2
θ
=
∫
π
0
d
θ
=
−
π
Read lesson note on Integration (JAMB)
Integration
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