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Find the value of ∫π0cos2θ−1sin2θdθ

Question 1 Report

Find the value of $\int_{0}^{π} \frac{c o s^{2} θ - 1}{s i n^{2} θ} d θ$

π

π/2

-π/2

-π

Answer Details

\int_{0}^{π} \frac{c o s^{2} θ - 1}{s i n^{2} θ} d θ = \int_{0}^{π} \frac{- s i n^{2} θ}{s i n^{2} θ} = \int_{0}^{π} d θ = - π

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Integration

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