The amplitude of a particle executing simple harmonic motion in 5cm while its angular frequency is 10 rad s-1. calculate the magnitude of the maximum accele...
Question 1 Report
The amplitude of a particle executing simple harmonic motion in 5cm while its angular frequency is 10 rad s-1. calculate the magnitude of the maximum acceleration of the particle
Answer Details
The maximum acceleration of a particle in simple harmonic motion is given by the product of the square of the angular frequency and the displacement of the particle from the equilibrium position. That is, amax = -ω2A Where, A is the amplitude of the particle, and ω is the angular frequency. Substituting the given values, we get: amax = - (10 rad/s)2 x 0.05 m amax = - 5 m/s2 or 5 ms-2 Since the maximum acceleration is a scalar quantity, we take its magnitude, which is simply 5 ms-2. Therefore, the correct option is 5.00ms-2.
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