The apparent weight of a body fully immersed in water is 32N and its weight in air is 96N. Calculate the volume of the body. [Density of water = 1000kgm-3, ...

Assessment: WAEC SSCE - Physics - 2001 (Objective) Subject: Physics

Question 1 Report

The apparent weight of a body fully immersed in water is 32N and its weight in air is 96N. Calculate the volume of the body. [Density of water = 1000kgm^-3, g = 10ms^-2]

8.9 x 10^-3m³

6.4 x 10^-3m³

3.2 x 10^-3m³

3.0 x 10^-3m³

Answer Details

The apparent weight of a body in a fluid is equal to the weight of the fluid displaced by the body. Using this principle, we can calculate the volume of the body as follows: Let V be the volume of the body Density of water = 1000kgm^-3 Weight of the body in air = 96N Weight of the body in water = 32N We know that: Weight of the body in air - Weight of the body in water = Upthrust = Weight of the water displaced Therefore, 96N - 32N = Weight of the water displaced 64N = Weight of the water displaced Weight of water displaced = Volume of body x Density of water x g 64N = V x 1000kgm^-3 x 10ms^-2 V = 64N / (1000kgm^-3 x 10ms^-2) V = 6.4 x 10^-3m³ Therefore, the volume of the body is 6.4 x 10^-3m³. Answer is correct.

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The apparent weight of a body fully immersed in water is 32N and its weight in air is 96N. Calculate the volume of the body. [Density of water = 1000kgm-3, ...

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