In triangle PQR, q = 8 cm, r = 6 cm and cos..

Question 1 Report

In triangle PQR, q = 8 cm, r = 6 cm and cos P = $\frac{1}{12}$ . Calculate the value of p.

\sqrt{108}

9 cm

\sqrt{92}

10 cm

Answer Details

Using the cosine rule, we have

$p^{2} = q^{2} + r^{2} - 2 q r \cos P$

$p^{2} = 8^{2} + 6^{2} - 2 (8) (6) (\frac{1}{12})$

= $64 + 36 - 8$

$p^{2} = 92 ∴ p = \sqrt{92} c m$

In triangle PQR, q = 8 cm, r = 6 cm and cos P = 112 1 12 . Calculate the value of p.