The potential difference between two points A and B situated at a distance d apart is V. Which of the following expresses the magnitude of the electric fiel...

Assessment: WAEC SSCE - Physics - 1993 (Objective) Subject: Physics

Question 1 Report

The potential difference between two points A and B situated at a distance d apart is V. Which of the following expresses the magnitude of the electric field intensity between the two points assuming the field is uniform?
Answer Details
The correct expression that expresses the magnitude of the electric field intensity between two points A and B situated at a distance d apart is, which is Vd-1. The electric field intensity is defined as the amount of electric force acting per unit charge. The potential difference between two points is defined as the work done per unit charge in moving a positive charge from one point to another. Hence, the electric field intensity E between the two points A and B can be obtained by dividing the potential difference V by the distance d between the two points. Therefore, E = V/d, which is equivalent to Vd-1.

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