A body timed 20 oscillations of a certain pendulum three times and obtained 44.3s, 45.5s and 45.7s respectively. Calculate the mean period of oscillation of...

Assessment: WAEC SSCE - Physics - 1993 (Objective) Subject: Physics

Question 1 Report

A body timed 20 oscillations of a certain pendulum three times and obtained 44.3s, 45.5s and 45.7s respectively. Calculate the mean period of oscillation of the pendulum
Answer Details
To calculate the mean period of oscillation, we need to find the time taken for one oscillation (the period) for each of the three trials, and then take the average. Let's start by calculating the time taken for one oscillation for each trial. For the first trial, the time taken for 20 oscillations is 44.3 s, so the time taken for one oscillation is: Time for 1 oscillation = 44.3 s ÷ 20 = 2.215 s Similarly, for the second trial: Time for 1 oscillation = 45.5 s ÷ 20 = 2.275 s And for the third trial: Time for 1 oscillation = 45.7 s ÷ 20 = 2.285 s Now, we can calculate the mean period of oscillation by taking the average of these three values: Mean period of oscillation = (2.215 s + 2.275 s + 2.285 s) ÷ 3 ≈ 2.26 s Therefore, the mean period of oscillation of the pendulum is approximately 2.26 s. The correct answer is 2.26s.

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